3x^(2/3)-8x^(1/3)-3=0

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Solution for 3x^(2/3)-8x^(1/3)-3=0 equation:


x in (-oo:+oo)

3*x^(2/3)-(8*x^(1/3))-3 = 0

3*x^(2/3)-8*x^(1/3)-3 = 0

t_1 = x^(1/3)

3*t_1^2-8*t_1^1-3 = 0

3*t_1^2-8*t_1-3 = 0

DELTA = (-8)^2-(-3*3*4)

DELTA = 100

DELTA > 0

t_1 = (100^(1/2)+8)/(2*3) or t_1 = (8-100^(1/2))/(2*3)

t_1 = 3 or t_1 = -1/3

t_1 = -1/3

x^(1/3)+1/3 = 0

1*x^(1/3) = -1/3 // : 1

x^(1/3) = -1/3

( -1/3 < 0 i 1/3 in (0:1) ) => x należy do O

t_1 = 3

x^(1/3)-3 = 0

1*x^(1/3) = 3 // : 1

x^(1/3) = 3

x^(1/3) = 3 // ^ 3

x = 27

x = 27

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